Multiplicative inverses for elements in field

Question

How to compute multiplicative inverses for elements in any simple (not extended) finite field? I mean an algorithm which can be implemented in software.

score 6 · Accepted Answer · answered Jul 26 '11 at 17:36

6

The unit group of the finite field of order $q$ is a cyclic group of order $q-1.$ Thus, for any $a \in \mathbb{F}_q^{\times},$ $$a^{-1} = a^{q-2}.$$

answered Jul 26 '11 at 17:36

jspecter

8,152

score 4 · Answer 2 · edited Apr 13 '17 at 12:20

4

In both cases one may employ the extended Euclidean algorithm to compute inverses. See here for an example. Alternatively, employ repeated squaring to compute $\rm\:a^{-1} = a^{q-2}\:$ for $\rm\:a \in \mathbb F_q^*\:,\:$ which is conveniently recalled by writing the exponent in binary Horner form. A useful reference is Knuth: TAoCP, vol 2: Seminumerical Algorithms.

edited Apr 13 '17 at 12:20

Community

1

answered Jul 26 '11 at 17:40

Bill Dubuque

272,048

score 2 · Answer 3 · answered Jul 26 '11 at 17:37

If 'simple' means a prime field $\mathbf{Z}/p\mathbf{Z}$ to you, then, given an integer $x$ coprime to $p$, you simply need to find an integer $y$ such that $xy\equiv1\pmod{p}.$ Look up the paragraph of multiplicative inverses in the wikipedia page on Euclidean algorithm

Multiplicative inverses for elements in field

3 Answers3