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Why does $\lim_{n\to\infty} \frac{n!}{(n-k)!n^k}$ equal 1
Asked
Oct 15 '13 at 11:18
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Apr 13 '19 at 07:43
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Came across this in my maths book.
$$\lim_{n\to\infty} \frac{n!}{(n-k)!n^k} = 1$$
Why is it so?
calculus|limits|factorial
edited Apr 13 '19 at 07:43
Martin Sleziak
53,687
asked Oct 15 '13 at 11:18
davl
49
Some other posts about the same problem:
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Limits involing Factorials $\lim_{N\to\infty} \frac{N!}{(N-k)!N^{k}}$
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Why $ \lim_{n\rightarrow \infty} \frac{n!}{n^{k}(n-k)! } =1 $?
,
–
Martin Sleziak
Apr 13 '19 at 07:48
0 Answers
0
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Limit question with factorials
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Why $ \lim_{n\rightarrow \infty} \frac{n!}{n^{k}(n-k)! } =1 $?
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Finding limit of sequence: $\lim _{n \to \infty} {\frac{n!}{n^k(n-k)!}}=1$
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Proof that $\lim\limits_{h \to \infty} \frac{h!}{h^k(h-k)!}=1 $ for any $ k $
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Limits involving factorials $\lim_{N\to\infty} \frac{N!}{(N-k)!N^{k}}$