What do I need to know to prove this? $ \frac{2\sqrt{2}}{9801} \sum_{k=0}^\infty \frac{ (4k)! (1103+26390k) }{ (k!)^4 396^{4k} } = \frac1{\pi} $

Question

This is an identity put forward by Ramanujan (often used as "proof" of his genius):

$$ \frac{2\sqrt{2}}{9801} \sum_{k=0}^\infty \frac{ (4k)! (1103+26390k) }{ (k!)^4 396^{4k} } = \frac1{\pi} $$

How does one go about proving this? Alternatively, what does one need to know to be able to do so?

Any help is appreciated.

Shobhit · Accepted Answer · 2013-09-27T19:38:20.077

3

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edited Sep 27 '13 at 19:38

answered Sep 27 '13 at 19:31

Shobhit

Thanks! The links are really good, and since this has been marked as a dup I'll accept your answer. – Soham Chowdhury Sep 28 '13 at 02:38
2

@SohamChowdhury Hail Ramanujan – Shobhit Sep 28 '13 at 03:24

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