Let $M$ be an $n \times n$ matrix, then the $(i,j)$-submatrix of $M$ is the $n-1 \times n-1$ matriz $M_{ij}$ given by removing the $i$-th line and the $j$-th column from $M$. The $(i,j)$-minor is $m_{ij} = \det M_{ij}$ and the $(i,j)$-cofactor is $c_{ij} = (-1)^{i + j}m_{ij}$
Is there a way to define these things for linear maps in a coordinate free way? I'm looking for some way to, given $T \colon V \to V$ a linear map, define $S \colon W \to W$ where $W$ is a hyperplane of $V$ and such that given a basis $e = (e_1, \dots, e_n)$ of $V$, there exists a basis $f = (f_1, \dots, f_{n-1})$ of $W$ related to $e$ in some way such that the matrix of $S$ in $f$ is a submatrix of the matrix of $T$ in $e$.
Some of you might be wondering the motivation behind it all: I am revisiting some ideas in linear algebra in a coordinate free way, and I've stumbled into Cayley-Hamilton. The original algebraic proof uses the definition of cofactor, so I'm wondering how one would go about proving it without coordinates and without using topology (with topology there is a simple proof using the density of diagonalizable matrices, but this is too out of context).