What is the expansion of $2^{1-s}$?

Asked Jan 31 '24 at 16:22

Active Jan 31 '24 at 18:08

Viewed 56 times

I'm looking at Eqn. 12 here

I tried the power rule $a^m \div a^n = a^{m-n}$ to get $2^1 / 2^s$. But probably this is wrong.

Looking at the equation this should probably be $1/2^s$.

Can you help?

EDIT:

I see in this question that the same expression is written in reverse as $2^{s-1}$ so this may be literally 2 raised to the power of $(1-s)$.

edited Jan 31 '24 at 18:08

asked Jan 31 '24 at 16:22

zeynel

1

Your original understanding was right, $2^{1 - s} = \frac{2}{2^s}$. – ConMan Jan 31 '24 at 23:12

0 Answers0