$\int_0^{0,2}\frac{1-e^{-x}}{x}dx$
I was trying to compute integral,cause it'll look like alternative series.
I'm stuck and have troubles to calculate this integral.
in first task,that looked like this $$\sum_{n=1}^{\infty}(-\frac{2}{9})^n$$ accurate to $$\alpha=0,0001$$
I used principle of alternative series that I noticed,because $$\ a1=-\frac{2}{9}$$ $$\ a2=\frac{4}{81}$$ $$\ a3=-\frac{8}{729}$$ till $$\ a8=\frac{256}{43046721}$$
and I summarize till $\ a8$ and I made it accurate to $\ 0,0001$
I need to somehow make it like this,but I'm so confused...
Thanks for helping in advance!