I am confused about the 1d Fourier transform of the absolute value of $x$. In particular I'm confused why it doesn't show up on most Fourier-transform tables that I look for.
I'm using the convention $\mathcal{F}(f) = \int f(x) e^{-ikx} dx$. We can write $\| x \| = x \, \text{sgn}(x)$ and use the fact that $\mathcal{F}(\text{sgn}(x)) = \frac{2}{ik}$. Then:
$$ \begin{aligned} \mathcal{F}(\| x \|) &= \mathcal{F}(x \, \text{sgn}(x)) \\ &= (i \frac{d}{dk}) (\frac{2}{ik}) \\ &= -\frac{2}{k^2} \end{aligned} $$
But for whatever reason this Fourier transform doesn't seem to be on most of the tables I've looked up. For example, Wikipedia only lists $\| x \|^{\alpha}$ for $-1 < \alpha < 0$, and the same is true of the sources (Erdélyi, Kammler) that it cites. Plus I haven't found anyone asking the question on StackExchange! What's going on? Does nobody ever transform this function?
I think I have the right answer, but want to be sure that I'm not missing a delta-function term or something as I'm usually just guessing when it comes to those. So it would be nice to have a source that includes $\| x\|$ and, ideally, $\| x \|^{\alpha > 1}$ as well.