I am reading Mathematical Logic by Ian Chiswell and Wilfrid Hodges and have been trying to solidify my understanding of pages 24-26 (Section 2.6 - Arguments using 'not'). In this section, the authors start off by defining negation with the following sentence: "If $\phi$ is a statement, we write $\lnot \phi$ for the statement expressing that $\phi$ is not true."
Based on this, how do we know that the negation of a statement is unique? I hope the below examples will illustrate my point:
Cat Example 1: If $\phi$ is the statement "The cat is black", then $\lnot \phi$ is "It is not true that the cat is black"
Cat Example 2: If $\phi$ is the statement "The cat is black", then $\lnot \phi$ is "The cat is blue"
Inequality Example 1: If $\phi$ is the statement "$5 < 7$", then $\lnot \phi$ is "It is not true that $5 < 7$"
Inequality Example 2: If $\phi$ is the statement "$5 < 7$", then $\lnot \phi$ is "$5 \ge 7$"
Of these four examples/claims, I would agree (based on the above definition of negation) with Cat Example 1 and Inequality Example 1. I would not agree with Cat Example 2 because the cat not being black does not imply that it has to be blue (there are other colors the cat could be).
Similarly (and this is where I get confused because I think most people would disagree with me here and say that Inequality Example 2 is correct), I would also not agree with Inequality Example 2 because it implicitly assumes that if "$5 < 7$", then "$5 \ge 7$" is the only other, unique option (just like how Cat Example 2 assumed the if the cat was not black, then the cat being blue was the only other option).
Of course, the difference between Inequality Example 2 and Cat Example 2 is that it IS actually true that "$5 \ge 7$" is the only other option, but this requires prior knowledge/the assumption of the trichotomy property of natural numbers. This makes me think that I should remedy Inequality Example 2 by thinking of "$5 \ge 7$" not as the negation of $\phi$, but as a completely new statement which has to be derived. So, perhaps it should be the conclusion of the following derivation using the $(\to E)$ rule?:
$\lnot \phi$, $(\lnot \phi \to \psi)$
$\therefore \psi$
where $\phi$ is "$5 < 7$", $\lnot \phi$ is "It is not true that $5 < 7$", and $\psi$ is "$5 \ge 7$".
Lastly, and I'm hoping I have written this post to be clear enough on its own, but for added context, this post is a follow-up to one I posted here the other day.