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I was trying to think of an example of a set that satisfies almost all of the properties of a group except associativity for pedagogical purposes. Two examples I came up with are: moving around on a spiral staircase, and hysteresis in a magnet. In each case, it was trivial to define a binary operation on the transitions (vector steps add as vectors to produce a new straight line path, adding changes in applied field as normal numbers). The problem I ran into is that the examples actually fail at the level of the result of the binary operation to combine transformations doesn't produce a unique equivalent transformation for all states in the space the transformations are defined on. My instinct is telling me that the problem is that the pole/hysteresis are in the space the transformations are defined on, and not in the space of transformations, itself, but I'm not sure.

In detail, is there an example of: a set $G$, a binary operation $\cdot$, and a definition of equality/equivalence between elements of $G$ such that:

  • closure: $\forall\ g,\ h \in G:\ g\cdot h \in G,$
  • identity element $e$: $\forall\ g \in G:\ g\cdot e = g,$
  • inverse element: $\forall g\in G:\ g\cdot g^{-1} = e,$ and
  • non-associativity: there exists $g,\ h,\ k \in G$ such that $(g\cdot h) \cdot k \neq g \cdot (h\cdot k).$

Ideally, the equality would be defined as follows: $g = h$ iff $g(s) = h(s)\ \forall s \in S$, where $S$ is a set of states on which the elements of $G$ are all automorphisms. Thus we need $[g\cdot(h\cdot k)](s) \neq [(g\cdot h)\cdot k](s)$ for at least one $s\in S$ and one set of $g$, $h$ and $k \in G$. In other words, the binary operations combining elements in $G$ need to be done before the resulting operation is applied to an element of $S$.

Sean Lake
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    I think octonians are a classical example coming up in algebra – Steven Creech Aug 11 '23 at 19:33
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    For a simpler example, how about subtraction on the integers? – Chris Eagle Aug 11 '23 at 19:43
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    @ChrisEagle This doesn't quite work. As $0-x\neq x$, you also need to restrict to the non-negative integers and take absolute values in order to get an identity. (This is the accepted answer in the close-target.) – user1729 Aug 11 '23 at 20:13

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