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Consider the following elementary question and answer:

Q: Find all the real roots of $P(x)=x^2-x$.

A:

$x^2-x=0$

$x(x-1)=0$

$x=0$ or $x-1=0$

$x=0$ or $x=1$

$x=0,1$. End.

This is a typical answer given by elementary school students and teachers. However, I wonder whether this answer is actually correct or valid in the context of proofs, logic, and rigor. To me, this answer only proves "If $x^2-x=0$, then $x=0$ or $x=1$", and doesn't show the converse "If $x=0$ or $x=1$, then $x^2-x=0$". The first one is needed to show no other real roots exist, while the second is needed to show these are indeed roots, and both are needed to show that the set {0,1} contains all the roots.

Questions

  1. Do the statements in the answer have an if, then or an if and only if relationship? i.e., does the answer mean "$x^2-x=0 \iff x=0$ or $x=1$" or "$x^2-x=0 \Rightarrow x=0$ or $x=1$"?

    • I know that the iff relationship is true for all the equations in the answer, but I would like to know whether it is what is meant in this case, given that the iff symbol is not written down between the equations.
  2. Would the answer be correct in the eyes of a teacher who demands 100% rigor? Or would it be necessary to plug the values back into the polynomial to show the converse?

  3. Would writing the iff symbol before each equation be needed, correct, or bad practice (in proofs)?

  4. When a question says "$P(x)=C$. Solve for $x$.", is there a formal restatement of the question in symbolic logic?

Cynicrom
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    Of course it's rigorous enough! You're not expected to re-invent the wheel every time you solve an equation (by which I mean rigorously constructing the algebra which you use to solve it). As to your other question, it is an iff relationship, but you've missed a statement. It should be "$x=0$ or $x=1$ iff $x^2-x = 0$". Whether or not you need to use the symbol before every equation in a proof is a matter of style. Some profs are probably mad for it, while others wouldn't be too fussed. – H. sapiens rex Aug 03 '23 at 07:29
  • Most if not all the proofs I have seen only use implication in their arguments. For instance, "Since P, it follows that Q." Is there a way of expressing an iff relationship in proofs using English (without just omitting it or implying it implicitly)? Just stating "P iff Q" seems unnatural. – Cynicrom Aug 03 '23 at 07:33
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  • Iff. 2. "Plugging the values back" would be redundant hence blamable. 3. Iff (symbol or words) mandatory, to make explicit this is what you mean. 4. No: it is a request, not a statement.
  • – Anne Bauval Aug 03 '23 at 07:39
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    It is sometimes supremely helpful to add text to a solution. You could write "In the following calculation all transformations are equivalencies." and leave the lines as they are. – Lutz Lehmann Aug 03 '23 at 16:15
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    You might be interested in reading the paper "On Mathematicians' Different Standards When Evaluating Elementary Proofs" by M. Inglis, Juan Pablo Mejía-Ramos, Keith Weber, L. Alcock. – Gunnar Sveinsson Aug 03 '23 at 17:14
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    Abstract of the article mentioned by @Gunnar: "In this article, we report a study in which 109 research-active mathematicians were asked to judge the validity of a purported proof in undergraduate calculus. Significant results from our study were as follows: (a) there was substantial disagreement among mathematicians regarding whether the argument was a valid proof, (b) applied mathematicians were more likely than pure mathematicians to judge the argument valid, (c) participants who judged the argument invalid were more confident in their judgments than those who judged it valid, and – ryang Aug 04 '23 at 00:21
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    (d) participants who judged the argument valid usually did not change their judgment when presented with a reason raised by other mathematicians for why the proof should be judged invalid. These findings suggest that, contrary to some claims in the literature, there is not a single standard of validity among contemporary mathematicians." – ryang Aug 04 '23 at 00:21
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    If you wanted to make this more rigorous, you can say that by the fundamental theorem of algebra, all polynomials have the same number of (possibly complex) roots as the degree of the polynomial (counting multiplicities). As you have found 2 roots of a degree 2 polynomial, you have found all of the roots. – user317176 Aug 04 '23 at 01:45
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    @ryang Thanks for the summary of that article. Shocking results … not! – Bram28 Aug 04 '23 at 02:56
  • In each stage you can use $\Leftrightarrow$, then you can conclude $x^2-x=0 \land x\in\mathbb{R} \Leftrightarrow x=0 \lor x=1$ – Ivan Kaznacheyeu Aug 04 '23 at 08:07