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The Statement: Viewing $\mathbb{C}^n$ as an $n$-dimensional Hilbert space, we can view $U(n)$ as the group of linear isometries of $\mathbb{C}^n$.

(Definition: The unitary group $U(n)$ consists of all $A\in GL(n, \mathbb{C})$ with $AA^*=A^*A=I$, where $A^*=(\overline{A})^t$ is the adjoint matrix of an $n\times n$ matrix $A$.)

Source: Classical Descriptive Set Theory by Alexander S. Kechris.

My Question: I do not follow the statement at all, even after figuring out what Hilbert space and linear isometry are. Any clarification will be greatly appreciated.

Asaf Karagila
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Dick Grayson
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    Does this help you? https://math.stackexchange.com/questions/899230/what-is-the-difference-between-isometric-and-unitary-operators-on-a-hilbert-spac – Vercassivelaunos Jun 14 '23 at 05:06

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