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I've been casually reading up on group theory recently, and I want to get a really solid and motivated understanding of where all the definitions we use come from.

Notions like the center of a group seem utterly natural to give a name to; all those elements that commute with the whole group $G$, which is easily proven a subgroup.

Normal subgroups however are slightly more mysterious. Closure under conjugation by arbitrary $g \in G$ seems like a natural idea once we've decided we care about conjugation, but it's not obvious to me why this should be privileged above all other automorphisms.

Is conjugation provably unique in some significant way; why is there not some other use of group operations defining alternatively "inner" automorphisms? Why are normal subgroups so much more significant than other subgroups, closed under other automorphisms; can we justify conjugation's significance without hand-waving about later useful applications?

user6873235
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    Have you studied quotient groups yet? In my opinion they are the main reason why normal subgroups are so important. – Alex Provost May 11 '23 at 12:36
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    "can we justify conjugation's significance without hand-waving about later useful applications?" No. We basically can't do that with anything in math, the way math is traditionally taught. You don't learn why primes are important before you learn what primes are, you don't learn why continuity of functions is important before you learn what continuity is, and so on. I think it's unfair to expect to learn the extent of the importance of conjugations and normal subgroups before you have a decent handle on what they are, other a simple example or two and "it will be clear later". – Arthur May 11 '23 at 13:01
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    In a sense, "$Inn(G)$ to $Z(G)$ as $Aut(G)$ to $L(G)$", where $L(G)$ is the absolute center. See e.g. here: https://math.stackexchange.com/q/4401563/1092170 – citadel May 11 '23 at 13:14
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    @Arthur Perhaps that is true "how traditionally taught", but I have found that it's a lot more effective (if one has the time and space) to have at least some crucial concepts come up because, by doing a variety of examples, it becomes clear that a new concept is needed. Primes are actually a good example of this - "Why am I having trouble finding common divisors, teacher?" then gets an answer, there are special numbers we call primes. Even in this case, "moving" subgroups via multiplication can be used: "Teacher, why is gN not the same as Ng?" and then conjugation just makes it look nicer. – kcrisman May 11 '23 at 16:22
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    @kcrisman I agree that the traditional method hasn't exactly focused on curiosity and motivation, and that can be detrimental for fundamental understanding and joy. But in your example you have just pushed the problem one step back: "Teacher, why should we care about these 'cosets' anyways?" If you have a full class and a modern curriculum, at almost any level, you just cannot do curiosity-driven exploration of everything. There simply isn't time. – Arthur May 11 '23 at 17:43
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    Normal subgroups arise naturally out of considerations of morphisms. Conjugation then arises out of trying to characterize them intrinsically. You can ask for stronger "closure" properties, which lead to characteristic and fully invariant subgroups. See some of the discussion here. – Arturo Magidin May 12 '23 at 03:27
  • @Arthur good thing I'm not taking classes and am just casually catching up on things I missed or felt were under-motivated at university. After all, stackexchange isn't a class - part of the point of a site where you ask questions, is to get answers to the questions you otherwise have trouble getting answers for! – user6873235 May 12 '23 at 04:13
  • @Arthur "There simply isn't time" - Maybe the question is whether the "modern" curriculum focused on covering as much as possible as fast as possible is good. There are many different opinions on that which I won't adjudicate here, especially since no matter what the course, there will be some students with less curiosity on topic X than is needed to explore topic X from scratch. As to why we should care about cosets - true, I'm just saying that "moving subgroups" is more natural than conjugation. If one doesn't think groups are interesting, none of this will matter to that person. – kcrisman May 12 '23 at 14:53

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Normal subgroups groups of a group $G$ are precisely those subgroups which are the kernels of group homomorphisms $f : G \to Q$.

In other words, a subgroup $N < G$ is normal if and only if there exists a group $Q$ and a homomorphism $f : G \to Q$ such that $$N = \{g \in G \mid f(g) = \text{Id}_Q\} $$ This is indeed very powerful in many applications of group theory. But it is also very important theoretically, for example it is the beginning of the concept of quotient groups. In fact, the proof of the "only if" direction usually proceeds by constructing an appropriate quotient group, namely $Q = G / N$.

Lee Mosher
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The reason normal subgroups are so important is because of their direct relation to quotient groups.

To answer your main question: if you believe that the center $Z(G)$ is a natural object, prove that $G/Z(G) \cong \operatorname{Inn}(G)$ holds for any group; this exhibits the inner automorphisms naturally as dual to the center.

From a pragmatic point of view, normalcy is nice because it lets you shift elements around. For example, say your group $G$ is made up of two complementary subgroups $N,H$, such that every element of $G$ can be written uniquely as $g = nh$ with $n\in N, h \in H$. If $N$ is normal, then you have a well-defined (not obviously so!) product operation on the set $N\times H \cong G$:

$$(n,h)(n',h') "=" nhn'h' = n(hn'h^{-1})hh' "=" (nn'',hh')$$

where $n'' = hn'h^{-1} \in N$ as been obtained through conjugation. This exhibits $G$ as a so-called semidirect product of its two subgroups, $G \cong N \rtimes H$. More generally you can replace conjugation by any homomorphism $H \to \operatorname{Aut}(N)$, but the result will be isomorphic to a semidirect product obtained via conjugation.

Alex Provost
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One of the most important ways of understanding groups is through their homomorphisms. For example, we tend not to consider groups up to isomorphism, which is defined as the existence of a bijective homomorphism between the groups. The first isomorphism theorem says that normal subgroups correspond to homomorphisms.

First Isomorphism Theorem. Let $G$ be a group. For every normal subgroup $N\lhd G$ there exists a group, written $G/N$, and a surjective homomorphism $\phi:G\to G/N$ such that $\ker(\phi)=N$.

Combining with the fact that the kernel of a homomorphism is necessarily normal, we therefore have a concrete equivalence between homomorphisms and normal subgroups.

(This is not "hand-waving about later useful applications", but the reason they are important!)


Subgroups which are closed under automorphisms are called characteristic. These are useful, but less so. For example, if $N$ is characteristic in $G$ then every automorphism of $G$ induces an automorphism of $G/N$, which is cute but also has hand-waving later applications in low dimensional topology and mapping class groups... :-)

user1729
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  • A useful property of characteristic subgroups is that if $H$ is characteristic in $K$, and $K$ is normal in $G$, then $H$ is normal in $G$; compare to how a normal subgroup of a normal subgroup need not be normal. – Arturo Magidin May 12 '23 at 14:47
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Take a group $G$, and a subgroup $H$. Color every element of $H$ red. Now pick a non-colored element $g_0$, find all the possible products $gh$ with $h\in H$ (this set is called $g_0H$), and color them blue. Pick a new non-colored element $g_1$, and color all the elements $g_1h$ for $h\in H$ green (this set of green elements is known as $g_1H$). Keep going until every element in $G$ has a color.

$H$ is normal iff this coloring itself makes a group with the inherited product (it is then called the quotient group $G/H$). In particular, we need that $hg_0$ also covers exactly all the blue elements (which is to say $g_0H = Hg_0$). This is the only way that multiplying a red element with a blue element always yields blue whichever order you multiply them. (Since the identity element is red, it cannot be any other color, and all these products have to yield the same color for the "color product" to be well-defined.)

We also need that $g_1h$ covers exactly all the green elements (i.e. $g_1H = Hg_1$). And so on through all the colors. This is exactly what normality is, although it's usually phrased as $gHg^{-1} = H$ rather than $gH = Hg$.


Note that we didn't have to start with coloring a subgroup. We could just do any coloring, and if the colors themselves then turn out to make a group, then we must have exactly one of the colorings described above. And the subset of $G$ consisting of elements that share a color with the identity will then be a normal subgroup. I just felt it was easier to describe this thing if we started with a subgroup.

Arthur
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The other answers are great. However, a take on it that doesn't have to do with quotients, and which might get to your underlying question, is that conjugation, in the matrix world, is just change of basis. (Or similarity, but I like this term better.)

Since change of basis for things like diagonalization $P^{-1}AP=D$ is pretty important, one can reason that in general one might want to examine this property. We have to be a little careful since $A$ might not be in the general linear group (invertible) itself for a general matrix $A$ that one does change of basis on, whereas all of the group elements will be in your question, but nonetheless it's an important thing to examine.

kcrisman
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