Ok, perhaps this portend an “Okay” explanation.
Consider F2(x) = F4 means:
F2 is the base field (with 2 elements)
F4 is the degree-2 extension field (with 4 elements)
x is an element of F4
The smallest subfield of F4 containing x is all of F4
As, x generates F4 as an extension of F2.
Only one element of F4 has this property (can generate the whole extension).
Now for the general case:
Fp is the base prime field
Fp6 is the degree-6 extension
α is an element of Fp6
Fp(α) = Fp6 means: the smallest subfield of Fp6 containing α is all of Fp6
In other words, α generates Fp6 as an extension of Fp
I believe the question is asking how many such "generator" elements α there can be. As I showed in my other replies, this depends on the minimum polynomial of α over Fp, and can be 1, p, p2, p3, p4, p5, or p6.