I was seeing some equations in WA, and i got with http://www.wolframalpha.com/input/?i=%28k%2B1%29%5E2%3E%3D4%28k-1%29%5E2
Let's manually solve the equation $$(k+1)^2\ge4(k-1)^2$$ $$(k+1)^2-(2k-2)^2\ge0$$ $$(-k+3)(3k-1)\ge0$$ But in alternate forms, it gives $$(k-3)\left(k-\frac13\right)\ge0$$ What is happening here?