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Question

Consider all ordered pairs of integers $(x,y)$ such that $$\frac{5}{x}+\frac{7}{y} = \frac{12}{xy}.$$ The smallest positive integer value of $x$ in these ordered pairs is 1, since $x=y=1$ satisfies the equation. What is the second smallest positive integer value of $x$ in these ordered pairs?

If I rearrange the equation I get $7x+5y=12$. I have been told that $5$ and $7$ are relatively coprime therefore solution will be of the format $(1+5n,1-7n)$

The bold Part in above argument is what I don't understand.

ACB
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1 Answers1

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Hint: If a prime $p$ divides $ab$ then either $p$ divides $a$ or $p$ divides $b$.

Now use it in the relation $7(x-1)=5(1-y)$.