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To solve a a DE rigorously, I'm not really sure how to set up the problem, in terms of definitions and premises.

So as a simple example, suppose we're given a function $f : \mathbb{R}^2 \rightarrow \mathbb{R},$ and we wish find the general solution to the first-order DE of the form $y'=f(x,y).$ My questions are as follows.

  1. Should we immediately define a function $S$ that takes a set $X$ and returns the set of all solutions on $X$, denoted $S_X$? In the sense of: $S_X = \{y : X \rightarrow \mathbb{R} \mid y'=f(x,y), \;y \mbox{ diff}\}.$

  2. Should we assume that we have a set $X$ (on which we're looking for solutions) that is fixed but arbitrary? If so, should we furthermore assume that $X$ is an interval? That its open? Does it need to be non-empty and/or have two or more elements?

  3. If the answer to any of the above questions is 'yes,' should we furthermore assume that we have a function $y : X \rightarrow \mathbb{R}$ that is fixed but arbitrary? If so, should we furthermore assume that $y$ is differentiable? That $y$ satisfies the DE? Note that, if the answer to this final question is 'yes', we can write this more simply as "Assume $y \in S_X$" so long as we've defined $S_X$.

  4. Is there anything else that needs to be done at the outset?

goblin GONE
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  • If people are being careful, they'll tell you exactly what they want when they ask you to solve a differential equation. For example they might give you an open interval $I \subset \mathbb R$, a number $t_0 \in I$, a number $y_0 \in \mathbb R$, and a continuous function $f:I \times \mathbb R \to \mathbb R$, and ask you to find a differentiable function $y:I \to \mathbb R$ such that $y'(t) = f(t,y(t))$ for all $t \in I$ and $y(t_0) = y_0$. Or something else like that. If you read about existence and uniqueness theorems for ODEs, hypotheses like this are stated carefully. – littleO Aug 08 '13 at 06:06
  • @littleO, I don't think that's an efficient way of going about it. Then you're solving every equation anew every time. You're better off first finding the general solution, and then plucking out the particular solution you're looking for. That way, if you're later looking for another particular solution, you don't have to do all that work all over again. So, I still don't know how to proceed to find the general solution. – goblin GONE Aug 08 '13 at 06:17
  • Yes, perhaps. Two comments that don't directly answer your question: 1) keep in mind that often there may not be any formula for a solution that you can write down. But given an initial condition, we can still solve the ODE numerically. – littleO Aug 08 '13 at 06:29
  • The standard existence and uniqueness theorems for ODEs shed some light on the situation here. Assume your $f$ is continuous. Given $t_0,y_0 \in \mathbb R$, there exists an open interval containing $t_0$ on which a solution to the ODE satisfying $y(t_0) = y_0$ exists. Let $I$ be the largest such interval. On this interval $I$, the solution (satisfying $y(t_0) = y_0$) is unique. (Please correct me if I'm stating these theorems wrong.)
  • – littleO Aug 08 '13 at 06:30
  • @littleO, it sounds about right, I don't know the theorems very well myself. So perhaps we should be assuming that $X$ is a maximum interval on which the solution exists? But I don't really think this is the right way to set the problem up, since it doesn't generalize to problems whose solutions have domains of dimension 2-or-higher. – goblin GONE Aug 08 '13 at 06:34