Question: $x(t)= -2 + 5cos(50\pi t +\frac{\pi}{3}) + 2sin(120\pi t)$, where t is in seconds. Find the fundamental period for this signal. What is its frequency in Hertz and in radians per second?
My attempt: $$T_1 = \frac{2\pi}{\omega}=\frac{2\pi}{50\pi}=1/25$$ $$T_2 = \frac{2\pi}{\omega}=\frac{2\pi}{120\pi}=1/60$$
LCM of $T_1 \ \& \ T_2$ is $\frac{1}{5}$, hence:$$T=\frac{2\pi}{\omega}=\frac{1}{5}$$ $$\omega=10\pi$$
Frequency in rps would be $10\pi=31.4159$ and the frequency in Hertz is $5$.
My hesitation here is how does the initial $-2$ term make a difference if at all?
