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I have been trying to understand the concepts that I didn’t fully grasp in high school calculus level lately, and it has been in the area of trig where I have the most trouble. So, as I have understood, the unit circle lets mathematicians define the functions sine cosine and tangent on a way that allows them to have the value of any real input, which is interpreted as the angle created by traveling along the circle counterclockwise with the X axis. I understand how to represent any point in the first quadrant using the cos and sin but I am not sure if it makes sense for the rest of the circle. If we take any other point in the circle, belonging to another quadrant, then the cosine or sine of that angle bigger than 90 degrees is not defined clearly, since what we should do is take actually the reference angle in the first quadrant and then build our triangle to get the correct ratios multiplied by its corresponding sign depending on where the point ended up due to the input angle initially. So this is what tricks me, I am not “satisfied” by accepting that the ways the trig function is defined for values greater than 90 and below 360 are actually the values of that same trig function but taking a value between 0 and 90 and scaling by +1/-1 depending on where the point is (which is seen by moving counterclockwise until reaching the angle given ) It discomforts me accepting this without confirmation since I feel like then the trig functions could have been more easily defined by just saying that it’s actual domain is 0-90 degrees because at the end that’s really what it computes by differing on a sign based on the quadrant. It feels like any input above 90 actually doesn’t get accepted directly and has to be correctly reduced into the 0-90 interval, taking into account the sign as well by its unit circle reasoning behind.

Suzu Hirose
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  • Please insert some line breaks. 2. Don't use capslock. 3. The way the trigonometric functions are defined is by taking the projection of the point $P(1,\theta)$ on the $x,y$ axes for cosine, sine and the slope of the line $OP$ for tan. The method you mention is simply an easy "trick" to get to the values.
  • – Cathedral Aug 27 '22 at 11:05
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