If $M$ is a smooth manifold, how do I interpret an expression such as $f X$ where $f \in C^{\infty}(M)$ and $X$ is a vector field, i.e. a map $M \rightarrow TM$?
To my understanding, a vector field is a derivation, a map with certain properties. I imagine it as the set of "directions" in each point of the manifold.
Now I came accross the definition of a covariant derivative of (smooth) vector fields $X, Y$, which confuses me. The properties satisfied by the covariant derivative are the following:
- $\nabla_{fX + gY} Z = f \nabla_X Z + g \nabla_Y Z$
- $\nabla_X (Y + Z) = \nabla_X Y + \nabla_X Z$
- $\nabla_X (fY) = X(f)Y + f \nabla_X Y$
My question: What does the $f X$ says? If $f$ just takes points from $M$ and assigns them a value (I guess in $\mathbb{R}^n$?), then how can it be multiplied or composed with a vector field that goes from $M$ to the tangent space? And what is the difference between $X(f)$ and $fX$ in the conditions?
Thank you very much.