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The problem arises from Walter Rudin's Real & Complex Analysis: enter image description here

The highlighted texts, however, would NOT make any sense if $A$ is not measurable. All my attempts to show that $A\in\mathfrak{M}$ have failed; any hints would be greatly appreciated.

Dick Grayson
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1 Answers1

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$$ A =\bigcap_{N=1}^\infty \bigcup_{n\ge N} E_k $$

By definition, this means any point of $A$ belongs to infinitely many of $E_k$. By the fact that $E_k$ are all measurable, you conclude $A$ is as well.

Son Gohan
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