0

Why the formula given in the answer here tells us that this group must be cyclic?

A group of order 561 is cyclic.

Here is the answer there:

In general, there is only one group of order $n$ iff gcd$(n,\varphi(n))=1$. Of course such a group must be necessarily cyclic. 561 satisfies the condition.

Shaun
  • 44,997
Brain
  • 1,003

1 Answers1

3

Because obviously there exists a cyclic group of order $n$ (namely $\{ 0, 1, 2, \ldots, n-1 \}$ with addition modulo $n$), so if there is a unique group of that order, it must be the cyclic one.

Adayah
  • 10,468