I'm trying to wrap my head around the sum of the first $k^{th}$ powers.
I understand the sum of the first n powers of 1, $n(n+1)/2$.
In order to reach the sum of the first n squares, I attempted to square the whole thing. But I seem to have arrived at the sum of the first n cubes.
$$\left(\frac{n(n+1)}2\right)^2=\frac {n^2(n+1)^2}{4}.$$
I've looked at derivations of all the formulas and they make sense to me, but I'm curious about why my approach landed me where it did. Note, I'm currently taking Calculus 2.