Suppose the reals are defined as the metric completion of $\mathbb Q$, using Cauchy sequences. They inherit an ordering from $\mathbb Q$ and it suffices to prove that $\mathbb Q_+ \cdot \mathbb Q_+ \subset \mathbb Q_+$.
Now $\mathbb Q$ is defined as the fraction field of $\mathbb Z$. An explicit construction is as pairs $(a, b) \in \mathbb Z \times (\mathbb Z - \{0\})$ modulo the equivalence relation of being proportional by a nonzero integer. The multiplication is entrywise, and it is not hard to define $\mathbb Q_+$ once you have defined $\mathbb Z_+$, and to reduce the question to proving that $\mathbb Z_+ \cdot \mathbb Z_+ \subset \mathbb Z_+$.
Now $\mathbb Z$ is constructed out of $\mathbb N$ and (practically by definition) $\mathbb Z _+ = \mathbb N$, and $\mathbb Z_+ \cdot \mathbb Z_+ \subset \mathbb Z_+$ is then true because the multiplication on $\mathbb Z_+$ is the same as the one on $\mathbb N$.