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I want to show that $\mathbb{K}[X,Y]/(XY-1) \cong \mathbb{K}[T,T^{-1}]$ and I’ve asked myself it is possible to show this by using the euclidean division of a polynomial in $\mathbb{K}[X,Y]/(XY-1)$?

user26857
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vitalmath
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1 Answers1

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The isomorphism is $X \to T$, $Y \to T^{-1}$. Just try it out the details are not hard. The intuition is that in $\mathbb{K}[X,Y]/(XY-1)$, the relation $XY = 1$ means that $Y$ is now the multiplicative inverse of $X$ (so, serves the same purpose as $X^{-1}$).

C Bagshaw
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  • Please do not answer questions, where not enough effort is shown. The OP asked almost the same question yesterday and has deleted it now. For a discussion on the quality standards of this site see here. – Dietrich Burde Feb 03 '22 at 09:10