Lets take Definition:
Example:
Then f(x) is not a measurable function, because ${f^{-1}}$({3,4}) $:=$ {1,2} $\not\in \Sigma $. Is this correct ?
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Yes, this is correct. – TheSilverDoe Jan 19 '22 at 14:32
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Thank you very much. – kolo kolo Jan 19 '22 at 15:24