Theorems $1$ and $2$ imply $A.$
Theorem $1$ and Theorem $2$ imply $A.$
The first phrasing is a tad more idiomatic than the second one, but nonetheless, they are in practice equivalent: each can be construed as either statement $(\text A1)$ or statement $(\text A2)$ below (admittedly, the $(\text A1)$ reading is a little more immediate)!
Suggestions:
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$(\text{Theorem 1} \wedge \text{Theorem 2}) \implies A\tag{A1}$
Theorems $1$ and $2$ collectively/together/jointly/conjunctively implies $A.$
$(\text{Theorem 1} \implies A) \land (\text{Theorem 2} \implies A) \tag{A2}$
Theorems $1$ and $2$ each implies $A.$
Notice that adding the word ‘both’ to the two phrasings at the top doesn't aid disambiguation.
Theorem $1$ or $2$ implies $A.$
Theorem $1$ or Theorem $2$ implies $A.$
You didn't ask, but these ‘or’ phrasings have the same issue as above.
Suggestions:
$(\text{Theorem 1} \lor \text{Theorem 2}) \implies A\tag{O1}$
If Theorem $1$ or $2$ is true, then $A$ is true.
Theorems $1$ and $2$ each implies $A.\quad$ (I.e., statement $(\text A2)$.)
$(\text{Theorem 1} \implies A) \lor (\text{Theorem 2} \implies A) \tag{O2}$
Theorem $1$ implies $A$ or Theorem $2$ implies $A.$
Theorems $1$ and $2$ jointly implies $A.\quad$ (I.e., statement $(\text A1)$; proof)