Let $f$ be a function homogeneous of degree $d$ in an $n$-dimensional space. Then its Fourier transform is also homogeneous, but of degree $-(n+d)$:
$$
\hat{f}(c\xi)
= \int f(x) e^{-ix\cdot c\xi} \, dx
= \int f(x) e^{-icx\cdot \xi} \, dx
= \int f(y/c) e^{-iy\cdot \xi} \, |c|^{-n} dy
\\
= \int c^{-d} f(y) e^{-iy\cdot \xi} \, |c|^{-n} dy
= c^{-(n+d)} \int f(y) e^{-iy\cdot \xi} \, dy
= c^{-(n+d)} \hat{f}(\xi).
$$
With $n=2$ and $d=-1,$ which is your case, we get
$$
\hat{f}(c\xi)
= c^{-1} \hat{f}(\xi)
$$
implying that $\hat{f}(\xi) = C|\xi|^{-1}.$ This verifies your relationship modulo the value of the constant $C$.