To calculate the maximal order of an element of the symmetric group $S_5$, I reasoned this way: if $\pi = \sigma_1 \cdots\sigma_t$ is a product of disjoint cycles (with orders $k_1,\dots, k_t$) then the order of $\pi$ is the least common multiple of $k_1,\dots, k_t$. By case-checking and symbol pushing, I was able to find that the maximal order of an element of $S_5$ is 6 (I noticed that $\pi$ can be written as (a b) or (a b c) or (a b c d) or (a b c d e) or (a b) (c d) or (a b)(c d e)). Is there way to calculate this number in general?
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The period of a cycle is its length, and the period of a product of disjoint cycles is the l.c.m. of the periods of its cycles. – Bernard Nov 13 '21 at 18:39
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1See https://oeis.org/A000793 – Jean Marie Nov 13 '21 at 18:40