In the famous paradox Russell tries to construct the set of all sets not containing itself. Then the question whether this whole set contains itself leads to a contradiction - if it does not contain itself then it should according to the definition, and if it does then it should not.
But let's consider the opposite construction - the set of all sets containing itself - and ask the same question: does this set contain itself?
It appears to me that both answers are consistent. If the set contains itself then it should (we are fine). But if it does not contain itself then it should not (we are also fine). We have no clue which option to prefer.
How should we interpret such a result?
- Does that mean that there are two such sets - one containing itself, another not?
- Or is it an example of a true statement which does not follow from any axioms (i. e. a manifestation of Godel's incompleteness) and we can choose either option as a separate axiom?
- Or is it still a kind of a paradox because a uniquely defined set has two instances?
Thanks in advance.
What about "This statement is true"? Again, naively it can be consistently both true or false and we have no reason to prefer either option. This seems to be a question of pure logic and does not require set theory. Does it depend on the definition of truth? I've seem a discussion on Lob's theorem and the question of "This statement is provable", but "This statement is true" seems to be a different matter.
– Ivan Rygaev Oct 28 '21 at 18:39