While solving the integrals related to $e^{x^2}$, we try to approximate it. My question is there some function of which the graph is approximately like that of $e^{x^2}$?
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Тyma Gaidash
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Preet
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That depends on the interval for integration. – Laxmi Narayan Bhandari Sep 16 '21 at 14:06
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3You have been around for more than a year. Haven't you yet noticed that you are supposed to use MathJax around here? – José Carlos Santos Sep 16 '21 at 14:12
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Using the power series representation we have
$$e^{x^2}=\sum_{n=0}^{\infty}\frac{x^{2n}}{n!}=1+x^2+\frac{x^4}{2!}+...$$
Taking more terms will give a better and better approximation.

Alessio K
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The Taylor series for $e^{x^2}$ is $$1 + x^2 + \frac{x^4}{2} + O(x^6),$$ so that any function that you sum $1$ to an even power of $x$ will ressemble approximately the function you mention. Take a look at its behaviour in Wolfram Alpha.

Arc
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