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While doing a counting problem today, I stumbled upon the fact that the $n$th Fibonacci number $F_n$ can be written as: $F_n = \sum^{r \le n/2}_{r=0} {n-r \choose r}$

Does this mean that there is some counting "significance" of Fibonacci numbers?

A way to define or describe them in plain English them rather than just the usual recursive formula or mathematical notation?

1 Answers1

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$F_n$ has a nice combinatorial interpretation; it is the number of ways to tile a $1\times n$ rectangle with any number of squares and dominoes. This assumes the convention $F_0=F_1=1$.

For example, $F_4=5$, because of the five tilings below: $$ \begin{array}{|c|c|c|c|}\hline \;\;&\;\;&\;\;&\;\;\\\hline\end{array}\qquad \\ \begin{array}{|cc|c|c|}\hline \;\;&\;\;&\;\;&\;\;\\\hline\end{array}\qquad \begin{array}{|c|cc|c|}\hline \;\;&\;\;&\;\;&\;\;\\\hline\end{array}\qquad \begin{array}{|c|c|cc|}\hline \;\;&\;\;&\;\;&\;\;\\\hline\end{array}\qquad \\ \begin{array}{|cc|cc|}\hline \;\;&\;\;&\;\;&\;\;\\\hline\end{array}\qquad\\ $$ You can prove this combinatorial interpretation for $F_n$ by induction on $n$.

To prove $F_n=\sum_k \binom{n-k}{k}$, note that $\binom{n-k}{k}$ is the number of tilings which use exactly $k$ dominos. Above, we see that $\binom{4}0=1$ tiling uses zero dominos, $\binom31=3$ tilings use one domino, and $\binom22=1$ tiling uses two dominoes.

Mike Earnest
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