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The rate of change of area of a circle with respect to change in its radius is equal to its circumference, as shown below: $$\frac{dA}{dr} = \frac{d}{dr}(\pi r^2) = 2\pi r$$

The rate of change of volume of a sphere with respect to change in its radius is equal to its surface area: $$\frac{dV}{dr} = \frac{dV}{dr}(\frac{4}{3}\pi r^3) = 4\pi r^2$$

Is there a geometrical/mathematical explanation for this?

O.S.
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Starlight
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