Typically, we only use a handful of logical symbols in proofs. Instead of saying 'for all' we (sometimes) write $\forall$. Instead of 'there exists' we (sometimes) use $\exists$, etc. But this is not really the point. The art of writing good proofs involved good notation, but that is more of a side issue (unless you 'choose' some obscure, non-standard, and anti-intuitive notation). A good proof should be easy to read, follow a clear path, and explain the logical steps followed, with clear references to theorems. There are some general principles that can be followed to both discover a proof and for writing it in a pleasant way after you found it. I'll try to show-case some.
First principle: Give it a name! Consider the following: prove that a natural number is even if, and only if, the square of the number is even. Here is a proof: Suppose that a given natural number is even. Then it is twice some other natural number. But then the square of the first natural number is 4 times the square of the second natural number, and thus the square of the first number is even. Now assume that the square a given natural number is even, yet the number itself is odd. Then, the number can be written as twice some natural number plus one. But the square of twice some natural number plus one is one plus an even number, and thus is odd. This contradicts the assumption that the square of the first number is even. Thus, we conclude that the number was even in the first place.
This proof is correct but is horrible. Instead, consider the following: Let $n$ be a natural number. We wish to show that $n$ is even if, and only if, $n^2$ is even. Let us first assume that $n$ is even. Then we may write $n=2\cdot k$ for some $k\in \mathbb N$. And then, $n^2=4k^2$, an even number. Thus if $n$ is even it follows that $n^2$ is even. For the implication in the other direction, assume that $n^2$ is even but $n$ is odd. Then, we may write $n=2k+1$ for some $k\in \mathbb N$, and then $n^2=4k^2+4k+1$, an odd number. This contradicts the assumption that $n^2$ was even, thus $n$ can't be odd. This completed the proof that $n$ is even if, and only if, $n^2$ is even.
The two proofs are roughly the same length, but it is much easier to follow the second one. The reason is that as soon as I'm talking about an entity, I give it a name. After all, it's a lot easier to say "Hi Daniela" instead of "Hi to the person with the hat standing next to the supermarket, wearing a purple T-shirt running away from the t-rex while singing 'twinkle twinkle' in a strong Irish accent".
Notice also how I used short phrases to parse the logical flow of the proof. I announce which direction in the implication I'm about to prove. I also announce clearly when an implication was established. At the end of the proof I clearly state the proof ended, and why.
So, give things a name. But, don't give each and every thing a name, or your scrap of paper will soon be full of useless entities. Trial and error is your friend. It's also worth mentioning that in the proof above I could have used more logical symbols, such as "$n$ is even $\iff$ $n^2$ is even". This would make little difference, and is a quite of minor changes in style.
Next principle: unpack! Definition are there to encapsulate information for us. The human brain loves encapsulating information. It loves it so much that sometimes it refuses to un-encapsulate. But quite often, you have to. For instance, let us prove that $\lim _{n\to \infty }\frac{1}{n}=0$. First, we'll use the hand-waving technique. We'll wave our hands sufficiently well to convince one of the argument, and produce some levitation as well. So, we need to show that the quantity $\frac{1}{n}$ can be made arbitrarily small, when $n$ is large enough. Clearly ('clearly' is a great word to use in hand-wavy arguments), when $n$ is very big, the fraction $\frac{1}{n}$ is very small, and get closer and closer to $0$. Thus, the desired limit is $0$.
This is of course not a proof. To turn this intuitively correct argument into a proof, we need to unpack the meaning of $\lim _{n\to \infty }\frac{1}{n}=0$. Here goes then. Proof of the above: Well, it means that for all $\epsilon >0$ there exists $K\in \mathbb N$ such that $|\frac{1}{n}|<\epsilon$ for all $n>K$. So, let (i.e., give it a name!) $\epsilon>0$. By the archamedean property of the natural numbers, there is a natural number $K$ such that $K>\frac{1}{\epsilon }$. But then, $\frac{1}{K}<\epsilon$ and so for all $n>K$ it holds that $\frac{1}{n}\le \frac{1}{K}<\epsilon$. The proof is complete.
Again, I could have used more logical symbols above, like $\exists$ and $\forall$, but that is minor stylistic issues.
I hope this answer is useful.