By degree of the equation, I know that there has to be 2 asymptotes. I have applied the general procedure to find the asymptotes as follows:
- Separate the terms of the equation in according to its degree. So I get $\phi_2=(x^2-2xy)$ and $\phi_1=(-2x-3y)$
- Then I put $x=1$ and $y=m$ in $\phi_2$ to get $m=1/2$
- Next I find $c= \frac{-\phi_1}{\phi_2'}$ to get $c=-7/4$
- Thus I get only one asymptote: $y=\frac{x}{2}-\frac{7}{4}$
But how do I get second asymptote? Wolfram