I am trying to prove that the real projective space $\mathbb R\mathbb P^n$ is Hausdorff. This answer almost does what I want, except I am starting from the definition of $\mathbb R\mathbb P^n$ based on the quotient map $\pi:\mathbb R^{n+1}\setminus\{0\}\to\mathbb R\mathbb P^n$ sending each point to its span. Using this definition, the following theorem is necessary to make the argument in the cited answer work.
Let $U$ be an open subset of $\mathbb S^n$ and let
$$C(U)=\big(\mathbb R^*\big)U=\big\{x\in\big(\mathbb R^{n+1}\big)^*\,\big|\,x=\lambda t\text{ for some }\lambda\in\mathbb R^*,t\in U\big\}$$
denote the cone generated by $U$, where $A^*:=A\setminus\{0\}$. Prove: $C(U)$ is open in $\mathbb R^{n+1}$.
This is not as trivial as it might seem, because an open ball centered somewhere in $U$ whose intersection with $\mathbb S^n$ is contained in $U$ still might generate a cone that intersects $\mathbb S^n$ outside $U$. In fact, I have already proven that the cone generated by an open ball in $\mathbb R^{n+1}$ is open, so I only need to show that each point in $U$ is contained in an open ball in $\mathbb R^{n+1}$ whose associated cone does not intersect $\mathbb S^n\setminus U$. But I am stuck here.