We are asked to get to approximate the area between the function $f(x) = x^{2}$ and the $x$-axis from $x = 0$ to $x = 2$ in $10$ regular partitions. All types of Riemann sums are asked: Left endpoint, right endpoint, and the midpoint Riemann sum.
The width can be observed to be $\frac{2 - 0}{10} = \frac{1}{5}$.
For the left endpoint Riemann sum, we can write and simplify as
$$A = \frac{1}{5}\sum_{i = 1}^{10}f\left(\frac{i-1}{5}\right)$$
When evaluated one by one, we get
$$A=\frac{1}{5}\left(\left(\frac{0}{5}\right)^{2} + \left(\frac{1}{5}\right)^{2} + \left(\frac{2}{5}\right)^{2} + \left(\frac{3}{5}\right)^{2} + \cdots + \left(\frac{7}{5}\right)^{2} + \left(\frac{8}{5}\right)^{2} + \left(\frac{9}{5}\right)^{2}\right)$$
Solving for this, we get $\frac{57}{25}$. However, it seems as if the process is too tedious. Is there a much more easier way for problems like this?
Edit: I am looking for ways to simplify the process of solving the Riemann sum of a general Riemann integrable function, not for an easier solution of the function that I mentioned.