Dear IBS, $dx$, $dy$ are just differentials of $x$ and $y$ respectively, so they're really $\Delta x=x_{\rm after}-x_{\rm before}$ and $\Delta y = y_{\rm after} - y_{\rm before}$ assumed to be infinitesimally small. The ordinary derivative $dy/dx$ is literally the radio of $\Delta y / \Delta x$ in the limit when $\Delta x$ is small.
The integral $\int dx\,f(x)$ is literally the sum (the sign $\int$ is supposed to be a mutated letter "S" that stands for "sum") of the products of $f(x)$ - height of a thin rectangle - and the infinitesimal variations $dx$ - the width of the thin rectangle - that have exactly the same meaning as in the previous paragraph - $\Delta x$ expected to be infinitesimally small. The notation is particularly natural for the Riemann integral but it is used for all axiomatic definitions of integrals.
The partial derivatives, $\partial y / \partial x_{i}$, requires a new symbol because in this case, we work with many independent variables $x_i$ and when we want to determine $dy$, i.e. how much it changes, we need to say not only how one of the $x_i$ variables changes, but how all of them change. So the partial derivative symbol $\partial$ is meant to be the same thing as $d$ but it also conveys the message that all the other variables $x_j$ instead of the actual $x_i$ that appears after $\partial$ in the denominator are kept constant.
For example, if you have $y=\sin(x_1)\exp(x_2)$, then
$$\frac{\partial y }{ \partial x_1} = \cos(x_1) \exp(x_2)$$
You couldn't just write $dy/dx_1$ on the left hand side because the "identity" wouldn't hold in general. It would only hold assuming that $x_2$ is constant, i.e. $dx_2=0$. More generally, we would have
$$dy = dx_1 \cos(x_1) \exp(x_2) + dx_2 \sin(x_1)\exp(x_2). $$
Note that you would have to erase the second term proportional to $dx_2$ if you wanted to write a simple expression for $dy/dx_1$: that's why $dy/dx_1$ is simply not equal to $\partial y / \partial x_1$ if there are many variables. So the special symbol for partial derivatives had to be introduced.