I have that $x_1, x_2,...,x_n$ are from a rv $X$ that has the density function $f_X(x)=\frac{2x}{\theta^2} \quad$ for $0 \le x \le \theta \quad$ and $f_X(x)=0 \quad$ otherwise. I have determined that $\theta^* = max(x_i)$. How Can I now calculate the CDF $F_{\theta^*}$, the pdf $f_{\theta^*}$ and the expectation $E[\theta^*]$ of the maximum likelihood estimator $\theta^*$?
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Related: https://math.stackexchange.com/questions/3976421/what-is-the-mle-theta-of-theta – Henry Jan 08 '21 at 00:17
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Hints:
- If the $x_1,\ldots, x_n$ are independent, then $P(\theta^* \le t) = P(x_1 \le t, x_2 \le t, \ldots, x_n \le t) = \prod_{i=1}^n P(x_i \le t)$
- $f_{\theta^*}(t) = \frac{d}{dt} F_{\theta^*}(t)$
- Use the usual formula for computing expectation when you have the density function

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