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When playing in a Python console I observed $\,\pi^\pi\approx 36.46\,$ and $\,e^e\approx 15.15$, and that their ratio is close to $\dfrac{12}{5} =$ a fraction with small numerator and denominator, hence $5\pi^\pi\approx 12\,e^e$.

Do you see a way to solve $$5\,\pi^\pi\;\stackrel{?}{\lessgtr}\; 12\,e^e$$ without calculator use ?

I would estimate that many Math.stackexchangers do not appreciate this kind of "without calculator" questions.
It is asked here in the hope that some elegant solution is found/presented, possibly in the spirit of
this awesome answer to $\pi^e\stackrel{?}{<} e^\pi$ as of ten years ago.

I have none to offer.
My approach was to consider the natural logarithm of the quotient $$\log\frac{\pi^\pi}{e^e} = \pi\log\pi - e\log e$$ and to relate it somehow to the definite integral of the logarithm $$\int_1^t\log x\:dx \;=\; t\,(\log t - 1) +1\,,$$ but without seeing a tangible result.

J. W. Tanner
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Hanno
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  • Using your integral idea, let $A = \int_e^\pi{\ln x} dx = \pi \ln \pi - \pi$. Comparing $A$ to the trapezoidal area that approximates it leads to a nice equality, $\ln \pi \ge \frac{3\pi-e}{\pi+e}$. This could be a useful intermediate step. – Théophile Feb 08 '23 at 20:31

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