how prove $\phi(n)\ge \frac{n}{6\log \log (n)} $ $\forall n\ge5 $

Asked May 20 '13 at 19:17

Active Nov 21 '13 at 14:19

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How to prove$\forall n\ge5 $

$$\phi(n)\ge \frac{n}{6\log \log (n)} $$

$\phi$ is Euler function

Thanks in advance

edited Nov 21 '13 at 14:19

Martin Sleziak

asked May 20 '13 at 19:17

M.H

3

See http://math.stackexchange.com/questions/101654/frac-n5-phi-n-n-for-all-n-1/101665#101665 for an even stronger result – Cocopuffs May 20 '13 at 19:51

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