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Prove the convergence of the following sequence:
$$x_1 = \sqrt{a}$$

$$x_{n+1} = \sqrt{a + x_n}$$

Amzoti
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    Welcome to MSE! Do you have any thoughts on the problem and can share your approach? It helps the MSE provide better feedback. Regards – Amzoti May 19 '13 at 17:21

2 Answers2

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Hint :

Prove that the sequence $\{x_n\}$ is bounded and monotonic

Dimitris
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(Of couse we need $a\ge 0$ as premise)

  1. Show by induction that $0\le x_n<a+1$

  2. Show by induction that $x_{n+1}\ge x_n$

(You can facilitate things a bit by prepending a term $x_0=0$. Not that then still $x_1=\sqrt{a+x_0}$)