How can I calculate $$ \int{\sec\left(x\right)\tan\left(x\right) \over 3x + 5}\,{\rm d}x $$
My Try:: $\displaystyle \int \frac{1}{3x+5}\left(\sec x\tan x \right)\,\mathrm dx$
Now Using Integration by Parts::
We Get $\displaystyle = \frac{1}{3x+5}\sec x +\int \frac{3}{(3x+5)^2}\sec x\,\mathrm dx$
Now My Question is How Can I calculate (II) Integral.
Please explain this to me.
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to indicate product; if you really want an explicit indication of it, then the TeX command\cdot
will provide you with a centred dot: $\cdot$. – Lord_Farin May 18 '13 at 08:04