Divisibility of Number Theory

Question

Can anyone explain this? I'm new to this topic. Prove that for all integers a, b, c , if a | c and b | c , then ab | c² .

Hint:as $a|c,b|c$, $c=ak,c=bm$ can you proceed – Albus Dumbledore Dec 11 '20 at 06:41 — Albus Dumbledore, Dec 11 '20 at 06:41

score 1 · Answer 1 · answered Dec 11 '20 at 06:59

1

That implies $c=ak$ and $c=bq$ so multiplying the EQ we get $c^2=ab(Kq)$ therefore $ab|c^2$

answered Dec 11 '20 at 06:59

Mehul

1 Answers1