There's a series as following. $$ \sqrt{3}, \sqrt{3 + \sqrt{3}}, \sqrt{3 + \sqrt{3 + \sqrt{3}}} + \cdots $$ Is there any way I can find the upper bound to prove the limit exist? I've tried to write down the formula of this series as following: $$ x_n = \sqrt{3 + x_{n - 1}} $$ but still find no way to modify it to get to the upper bound.
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More similar questions: https://math.stackexchange.com/questions/linked/115501 – Martin R Nov 05 '20 at 08:17
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Hint : Show inductively that all the terms are bounded by $$\frac{1+\sqrt{13}}{2}$$

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