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There's a series as following. $$ \sqrt{3}, \sqrt{3 + \sqrt{3}}, \sqrt{3 + \sqrt{3 + \sqrt{3}}} + \cdots $$ Is there any way I can find the upper bound to prove the limit exist? I've tried to write down the formula of this series as following: $$ x_n = \sqrt{3 + x_{n - 1}} $$ but still find no way to modify it to get to the upper bound.

ViktorStein
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Bi Ao
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1 Answers1

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Hint : Show inductively that all the terms are bounded by $$\frac{1+\sqrt{13}}{2}$$

TheSilverDoe
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