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Show each infinite set $S \subset \mathbb R$ contains a countably infinite subset.

I understand that if you remove an object from the set, it will still be infinite, and if we remove another object, it will be countably infinite (I think so at least). I'm very lost on this kind of proof. However if someone can help that would be appreciated.

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Clearly $S$ is nonempty so there is an element $a_1 \in S$. Then $S -\{a_1\}$ can’t be empty (as $S\neq \{a_1\} $since $S$ is not finite) and so we can pick $a_2 \in S -\{a_1\}$. Next pick $a_3 \in S - \{a_1, a_2\}$ inductively you will get a sequence and you are done!

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