I've been thought at school that the definition of $\exp(x)$ is the unique function satisfying $\exp'(x)=\exp(x)$ and $\exp(0)=1$. But I've never found this definition somewhere else. On Wikipedia there are multiple definitions which are : $$\exp(x)=\sum_{k=0}^{\infty}\frac{x^k}{k!}$$ $$\text{The solution $y$ to the equation }x=\int_1^y\frac{1}tdt$$ $$\text{and } \exp(x)=\lim_{n\to+\infty}\left(1+\frac{x}{n}\right)^n$$ As I know, something can have only one definition, but can have multiply ways to define it and properties. So which one is the real definition of the exponential function?
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4They are all completely equivalent definitions, and they are all equally "real" or "correct". – Milind Hegde May 04 '13 at 17:29
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@moray95 add "the inverse of $\log$" – Federica Maggioni May 04 '13 at 17:30
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The one you use to find most properties is the one with the series. But they are equivalent anyway. – xavierm02 May 04 '13 at 17:30
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When definitions are equivalent, mathematicians stop carrying which is "real". They will just use the one they like. – Christopher King May 04 '13 at 17:32
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I don't get "equivalent" definitions, a definition should be unique no? – moray95 May 04 '13 at 17:33
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@moray: No they needn't be. Equivalent definitions help when one definition is hard to manipulate but the other is easier. But it is necessary to show equivalence in the first place which need not be easy. – Gautam Shenoy May 04 '13 at 17:35
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Then the other one wouldn't be a property rather then a definition? – moray95 May 04 '13 at 17:39
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The inverse of log is the most appropriate definition as it is used in every possible definition – Kartikey May 04 '13 at 17:33
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http://math.stackexchange.com/questions/1427618/why-does-e-have-multiple-definitions – Aug 31 '16 at 01:01
3 Answers
The following are equivalent definitions for $\exp(x)$. \begin{align} 1. & f(x) = \sum_{k=0}^{\infty} \dfrac{x^k}{k!}\\ 2. & \dfrac{d f(x)}{dx} = f(x) \text{ with } f(0) = 1\\ 3. & f(x) = \lim_{n \to \infty} \left(1+\dfrac{x}n\right)^n\\ 4. & f(x+y) = f(x) \cdot f(y) \text{ with }f(x) >0 \text{ being continuous at one point and } f(1) = e \end{align} If you start with any one, you can derive/prove the others.
EDIT
The important thing is that you can start with anyone and derive the others as property. If a statement $A$ implies a statement $B$ and vice-versa, both are equivalent statements. We may, hence, use any one of them as a definition.
For instance, if you choose $(1)$ to define $\exp(x)$ as $\exp(x) = \displaystyle \sum_{k=0}^{\infty} \dfrac{x^k}{k!}$, the rest from $(2)$ to $(4)$ become properties.
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Then the one you start will be the definition and the other ones properties... – moray95 May 04 '13 at 17:35
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@moray95 Yes. But the important thing you can start with anyone and derive the other as properties. If a statement $A$ implies a statement $B$ and vice-versa, both are equivalent statements. We may, hence, use any one of them as a definition. – May 04 '13 at 17:38
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@moray95 For instance, if you choose to define $\exp(x) = \sum_{k=0}^{\infty} \dfrac{x^k}{k!}$, the rest become properties. – May 04 '13 at 17:40
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To address the comment below your question, and your assertion that something must have "one real" definition:
"Equivalent definitions" simply mean that there are many ways to define/describe $e^x$, all of which define/describe the unique function: $f(x) = e^x$. When definitions are equivalent, we can choose any one of them to derive the others. So we are free to choose which, among equivalent defintions, will serve our purpose best, depending on when and how we need to use it.
That is true of many mathematical entities: e.g., there is no *ONE* true definition of $\pi$: there are many ways to define the unique number $\pi$.

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Agreed, context matters and sometimes there are even slightly different definitions of things (just like the English language, which makes it really hard with potentially dozens of meanings for a single word). +1 – Amzoti May 05 '13 at 00:36
Another Wikipedia article of relevance is Characterizations of the exponential function.
Which characterization is most appropriate to take to be the definition depends on the context.