I'm currently doing high school second year trigonometry but this is just something that came to my mind.
The figure below shows a right angled triangle $ABC$, where $\angle A = \alpha$, $\angle B = \dfrac{\pi}{2}$ or $90^\circ$.
Now, in introductory trigonometry, the trigonometric functions of an angle are defined as ratios or sides of a right angled triangle. For example : $\sin\alpha = \dfrac{BC}{AC}$.
In the textbook I learned trigonometry from, this were the contents of the first few pages :
The first example was as follows :
You are provided with two triangles. Let those triangles be $XYZ$ and $PQR$. Both of these triangles are right angled triangles. $\angle Y = \angle Q = 90^\circ$. Also, $\angle X = \angle P$. Let these two angles be equal to $\varphi$. Now, $XZ = 5 \text{ units}$, $YZ = 3 \text{ units}$ and $PR = 10 \text{ units}$. Find $QR$.
The solution was as follows : $$\sin\varphi = \dfrac{\text{Perpendicular}}{\text{Hypotenuse}} = \dfrac{3}{5} \text{, obtained from } \Delta XYZ$$ $$\text{From }\Delta PQR \text{, } \sin\varphi = \dfrac{QR}{10}$$ $$\therefore \sin\varphi ~ \dfrac{3}{5} = \dfrac{QR}{10} \implies QR = \dfrac{10 \cdot 3}{5} = 6 \text{ units}$$
I think that prior to this,. the following statement should have been proved :
The trigonometric ratios of an angle are unique and do not depend on the triangle chosen.
I don't think think that this solution would be valid before proving that the sine of $\varphi$ obtained from both the triangles is unique. The statement that I have mentioned above can easily be proved using similarity but what I want to ask in this question is "Should statements like this, which are assumed to be obvious and trivial be proved before attempting questions like the example I gave and would the solution to this example be rendered as invalid if this statement has not been proved beforehand?"
Thank You!
in introductory trigonometry
– Rajdeep Sindhu Aug 19 '20 at 06:33