1

I'm looking for concrete examples of a countable Bernstein set and an uncountable Bernstein set. I haven't been able to find or construct any specific examples so far.

Newman
  • 1,033
  • 1
  • 10
  • 21

1 Answers1

5

Bernstein sets are non-measurable, so there are no concrete examples: assuming the existence of an inaccessible cardinal, it is consistent with $\mathsf{ZF}$ that all subsets of the reals are measurable.

All Borel sets are measurable, so there cannot be a countable Bernstein set.

Brian M. Scott
  • 616,228