0

That's my homework. I've been looking for "Taylor series" and trying to understand it. Seen some solutions but i think they're not that explanatory. Can you help me?

Sanicron
  • 19
  • 1
    This site is not a homework completion service. Please show your own efforts. – amWhy Jun 28 '20 at 17:55
  • $$\cos(43^\circ) = \cos(45^\circ-2^\circ) = \frac{\cos 2^\circ+\sin 2^\circ}{\sqrt{2}} = \frac{1-2\sin^2 1^\circ+\sin 2^\circ}{\sqrt{2}} $$ and the problem boils down to estimating $\sin 1^\circ$ and $\sin 2^\circ$, very close to $\frac{\pi}{180}$ and $\frac{\pi}{90}$. – Jack D'Aurizio Jun 28 '20 at 17:57
  • 1
    We just had this with error less than 8/60000. See this question – Ross Millikan Jun 28 '20 at 18:03

0 Answers0