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The probability of a single coin landing heads is $1/2$.
Using simple probability theory, this means that the probability of three coins landing heads is $1/2*1/2*1/2=1/8$

However, if we don't enumerate or distinguish the coins, the possible end combinations we see after flipping all three coins are
TTT
TTH
THH
HHH
Since one of these four is our desired combination of three heads, the probability would seem to be $1/4$.

Why isn't this the case?

1 Answers1

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Note that the cases TTH, THT and HTT are distinct because despite the coins are equal, the order of their toss matters (i.e. knowing that exactly 1 head drew is not enough, we must know at which toss did it happen).

Mostafa Ayaz
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